SOLUTION: can you please help me! Find the LCD of the fractions in the equation {{{(4.5x)/(2x+5)=(2x)/(x^2)}}} a.{{{(2x+5)(x)}}} b.{{{2x+5*x}}} c.{{{(2x+5)(x)(x)}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: can you please help me! Find the LCD of the fractions in the equation {{{(4.5x)/(2x+5)=(2x)/(x^2)}}} a.{{{(2x+5)(x)}}} b.{{{2x+5*x}}} c.{{{(2x+5)(x)(x)}}}       Log On


   

Question 190592: can you please help me!
Find the LCD of the fractions in the equation
%284.5x%29%2F%282x%2B5%29=%282x%29%2F%28x%5E2%29
a.%282x%2B5%29%28x%29
b.2x%2B5%2Ax
c.%282x%2B5%29%28x%29%28x%29
Found 2 solutions by jim_thompson5910, Alan3354:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Take note that the denominators are 2x%2B5 and x%5E2. Usually (not always), the LCD is simply the product of all the denominators. So just multiply 2x%2B5 and x%5E2 to get %282x%2B5%29x%5E2. Now just factor x%5E2 to get %28x%29%28x%29. So the LCD becomes %282x%2B5%29%28x%29%28x%29. So the answer is C


Note: you might see the LCD as x%5E2%282x%2B5%29 or %28x%29%28x%29%282x%2B5%29 (the factors are just rearranged)

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the LCD of the fractions in the equation
%284.5x%29%2F%282x%2B5%29=%282x%29%2F%28x%5E2%29
a.%282x%2B5%29%28x%29
b.2x%2B5%2Ax
c.%282x%2B5%29%28x%29%28x%29
--------------------------------
%284.5x%29%2F%282x%2B5%29=%282x%29%2F%28x%5E2%29
Reduce the right side
= %284.5x%29%2F%282x%2B5%29=2%2Fx
The LCD is x*(2x+5)