SOLUTION: Rewrite ln(6e^3/v^5)^6 as a sum or difference of terms if possible. Then simplify.
I worked it out to:
=6(ln 6e^3-ln v^5)
=6(ln 6 + ln e^3-ln v^5)
=6(ln 6+3ln e-5lnv)
=6(ln 6
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-> SOLUTION: Rewrite ln(6e^3/v^5)^6 as a sum or difference of terms if possible. Then simplify.
I worked it out to:
=6(ln 6e^3-ln v^5)
=6(ln 6 + ln e^3-ln v^5)
=6(ln 6+3ln e-5lnv)
=6(ln 6
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Question 190472This question is from textbook saxon algebra 2
: Rewrite ln(6e^3/v^5)^6 as a sum or difference of terms if possible. Then simplify.
I worked it out to:
=6(ln 6e^3-ln v^5)
=6(ln 6 + ln e^3-ln v^5)
=6(ln 6+3ln e-5lnv)
=6(ln 6+3(1)-5ln v)
=6ln 6+18-30ln v
Am I correct? This question is from textbook saxon algebra 2
You can put this solution on YOUR website! Rewrite ln(6e^3/v^5)^6 as a sum or difference of terms if possible. Then simplify.
I worked it out to:
=6(ln 6e^3-ln v^5)
=6(ln 6 + ln e^3-ln v^5)
=6(ln 6+3ln e-5lnv)
=6(ln 6+3(1)-5ln v)
=6ln 6+18-30ln v
Am I correct?
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ln(6e^3/v^5)^6
=6*(6ln(e^3)- ln(v^5))
= 6*(ln(6) + 3 - 5ln(v)) assuming e is the base and not just a variable
= 6ln(6) + 18 - 30ln(v) same answer.
