SOLUTION: The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter. A wire having length 2m and diameter 1.5mm stretc
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Question 190317This question is from textbook algebra and trigonometry structure and method book 2
: The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter. A wire having length 2m and diameter 1.5mm stretches 1.2 mm. If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch.
Please help as i keep on messing the decimals up and can't seem to get the right answer. Please explain also. thank you! This question is from textbook algebra and trigonometry structure and method book 2
You can put this solution on YOUR website! The stretch on a wire under a given tension varies directly as the length of the wire and inversely as the square of its diameter.
stretch = k[L/d^2]
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A wire having length 2m and diameter 1.5mm stretches 1.2 mm.
1.2 = k[2/1.5^2]
1.2 = k[8/9]
k = (9/8)1.2
k = 27/20
So the equation for your problem is stretch = (27/20)[L/d^2]
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If a second wire of the same material(and under the same tension) has length 3m and diameter 2.0mm, find the amount of stretch.
stretch = (27/20)[3/2^2] = 1.0125
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Cheers,
Stan H.
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