SOLUTION: sandy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.
Algebra ->
Customizable Word Problem Solvers
-> Coins
-> SOLUTION: sandy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.
Log On
Question 190237: sandy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify. Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! andy has $3.25 in change. She has five more dimes than quarters but twice as many nickels as dimes. Express the given information as an algebraic equation and simplify.
;
An equation for the total $
.05n + .10d + .25q = 3.25
:
"She has five more dimes than quarters"
d = (q + 5)
or
q = (d-5)
:
" but twice as many nickels as dimes."
n = 2d
:
Substitute for n and q in the $$ equation:
.05(2d) + .10d + .25(d-5) = 3.25
:
.10d + .10d + .25d - 1.25 = 3.25
Simplify:
.45d = 3.25 + 1.25
:
.45d = 4.50
:
They didn't say anything about solving it, but it's pretty easy now