Question 190085: Solve each equation 10b^2-15b=8b-12 Thank you
Found 2 solutions by Mathtut, bsmath:
Answer by Mathtut(3670)   (Show Source):
Answer by bsmath(21) (Show Source):
You can put this solution on YOUR website! 10b^2-15b=8b-12
Subtract the right-hand side of the equation from both sides:
10b^2-15b-8b+12=0
Now combine like terms:
10b^2-23b+12=0
Now it looks like we need the quadratic formula:
-b/2a +-((b^2-4ac)^1/2)/2a, where a is the coeffient of the b^2 term,
b is the coefficient of the b term, and c is the coefficient of the
integer term. So, a=10, b=-23, and c=12. Plugging in the values gives us:
b=23/20 +- (((-23)^2-(4)(10)(12))^1/2)/20. We now have
23/20 +-((529-480)^1/2)/20=23/20 +-((49)^1/2)/20=
23/20 +-7/20=30/20, 16/20=3/2, 4/5. Check the answer by plugging in the
values: 10(3/2)^2-23(3/2)+12=0, 90/4-69/2+12=90/4-138/4=12=-48/4+48/4=0.
You can check the second result the same way.
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