SOLUTION: Solve each equation. I am having trouble with this. 6d^2+21d=10d+35

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Question 190082: Solve each equation. I am having trouble with this. 6d^2+21d=10d+35
Found 2 solutions by Mathtut, Earlsdon:
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
6d%5E2%2B11d-35=0
:
%283d-5%29%282d%2B7%29=0
:
d=5/3 and d=-7/2

Answer by Earlsdon(6294) About Me  (Show Source):
You can put this solution on YOUR website!
Solve for d:
6d%5E2%2B21d+=+10d%2B35 First, get the equation into standard quadratic form:ax%5E2%2Bbx%2Bc+=+0 Subtact 10 d from both sides.
6d%5E2%2B11d+=+35 Now subtract 35 from both sides.
6d%5E2%2B11d-35+=+0 Now factor the trinomial.
%283d-5%29%282d%2B7%29+=+0 Apply the zero product rule.
3d-5+=+0 or 2d%2B7+=+0 so that...
3d+=+5 and highlight%28d+=+5%2F3%29 or
2d+=+-7 and highlight%28d+=+-7%2F2%29