Question 189913: can you please help me??
solve each equation. If the equation has no solution, choose no real solution.
Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! solve each equation. If the equation has no solution, choose no real solution.
[x/(x-5)] = [-2x/x]
Cross multiply to get
x^2 = -2x^2+10x
3x^2-10x = 0
x(3x - 10) = 0
x = 0 or 3x-10 = 0
x = 0 or x = 10/3
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But x cannot be zero in the original equation.
Ans: x = 10/3
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Cheers,
Stan H.
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