SOLUTION: find the coordinates of the vertex y=3x^2

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Question 189898: find the coordinates of the vertex
y=3x^2
Found 2 solutions by jim_thompson5910, nerdybill:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

In order to find the vertex, we first need to find the x-coordinate of the vertex.


To find the x-coordinate of the vertex, use this formula: x=%28-b%29%2F%282a%29.


x=%28-b%29%2F%282a%29 Start with the given formula.


From y=3x%5E2, we can see that a=3, b=0, and c=0.


x=%28-%280%29%29%2F%282%283%29%29 Plug in a=3 and b=0.


x=%28-0%29%2F%286%29 Multiply 2 and 3 to get 6.


x=0 Divide.


So the x-coordinate of the vertex is x=0. Note: this means that the axis of symmetry is also x=0.


Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.


y=3x%5E2 Start with the given equation.


y=3%280%29%5E2 Plug in x=0.


y=3%280%29 Square 0 to get 0.


y=0 Multiply 3 and 0 to get 0.



So the y-coordinate of the vertex is y=0.


So the vertex is .

Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!

The vertex form of a parabola is:
y= a(x-h)^2+k
where
(h, k) is the vertex
.
In your case, they gave you:
y=3x^2
.
Rewritten in "vertex form" we have"
y=3(x-0)^2 + 0
Therefore, the vertex is at (0,0)