SOLUTION: solving a polynomial equation -2h^2-28h-98=0

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Question 189892: solving a polynomial equation
-2h^2-28h-98=0
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

-2h%5E2-28h-98=0 Start with the given equation.


Notice we have a quadratic equation in the form of ah%5E2%2Bbh%2Bc where a=-2, b=-28, and c=-98


Let's use the quadratic formula to solve for h


h+=+%28-b+%2B-+sqrt%28+b%5E2-4ac+%29%29%2F%282a%29 Start with the quadratic formula


h+=+%28-%28-28%29+%2B-+sqrt%28+%28-28%29%5E2-4%28-2%29%28-98%29+%29%29%2F%282%28-2%29%29 Plug in a=-2, b=-28, and c=-98


h+=+%2828+%2B-+sqrt%28+%28-28%29%5E2-4%28-2%29%28-98%29+%29%29%2F%282%28-2%29%29 Negate -28 to get 28.


h+=+%2828+%2B-+sqrt%28+784-4%28-2%29%28-98%29+%29%29%2F%282%28-2%29%29 Square -28 to get 784.


h+=+%2828+%2B-+sqrt%28+784-784+%29%29%2F%282%28-2%29%29 Multiply 4%28-2%29%28-98%29 to get 784


h+=+%2828+%2B-+sqrt%28+0+%29%29%2F%282%28-2%29%29 Subtract 784 from 784 to get 0


h+=+%2828+%2B-+sqrt%28+0+%29%29%2F%28-4%29 Multiply 2 and -2 to get -4.


h+=+%2828+%2B-+0%29%2F%28-4%29 Take the square root of 0 to get 0.


h+=+%2828+%2B+0%29%2F%28-4%29 or h+=+%2828+-+0%29%2F%28-4%29 Break up the expression.


h+=+%2828%29%2F%28-4%29 or h+=++%2828%29%2F%28-4%29 Combine like terms.


h+=+-7 or h+=+-7 Simplify.


So the answer is h+=+-7