SOLUTION: Two 12mm sides of a rhombus for a 60 degree angle. Fine the area of the rhombus. I just dont understand.

Algebra ->  Parallelograms -> SOLUTION: Two 12mm sides of a rhombus for a 60 degree angle. Fine the area of the rhombus. I just dont understand.      Log On


   

Question 189851: Two 12mm sides of a rhombus for a 60 degree angle. Fine the area of the rhombus. I just dont understand.
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
One of the formulas for the area of a rhombus is A=s%5E2%2Asin%28x%29 where "s" is the length of the side and "x" is the angle given


A=s%5E2%2Asin%28x%29 Start with the given formula


A=12%5E2%2Asin%2860%29 Plug in s=12 and x=60


A=144%2Asin%2860%29 Square 12 to get 144


A=144%2A%28sqrt%283%29%2F2%29 Evaluate the sine of 60 to get sqrt%283%29%2F2 (use the unit circle)


A=%28144%2Asqrt%283%29%29%2F2 Multiply


A=72%2Asqrt%283%29 Reduce


... Approximate the right side using a calculator


So the area of the rhombus is about 124.708 square mm.