Question 189830: Factor completely
6a^2 – 6a - 72
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Start with the given expression
Factor out the GCF
Now let's focus on the inner expression
------------------------------------------------------------
Looking at we can see that the first term is and the last term is where the coefficients are 1 and -12 respectively.
Now multiply the first coefficient 1 and the last coefficient -12 to get -12. Now what two numbers multiply to -12 and add to the middle coefficient -1? Let's list all of the factors of -12:
Factors of -12:
1,2,3,4,6,12
-1,-2,-3,-4,-6,-12 ...List the negative factors as well. This will allow us to find all possible combinations
These factors pair up and multiply to -12
(1)*(-12)
(2)*(-6)
(3)*(-4)
(-1)*(12)
(-2)*(6)
(-3)*(4)
note: remember, the product of a negative and a positive number is a negative number
Now which of these pairs add to -1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to -1
First Number | Second Number | Sum | 1 | -12 | 1+(-12)=-11 | 2 | -6 | 2+(-6)=-4 | 3 | -4 | 3+(-4)=-1 | -1 | 12 | -1+12=11 | -2 | 6 | -2+6=4 | -3 | 4 | -3+4=1 |
From this list we can see that 3 and -4 add up to -1 and multiply to -12
Now looking at the expression , replace with (notice combines to . So it is equivalent to )
Now let's factor by grouping:
Group like terms
Factor out the GCF of out of the first group. Factor out the GCF of out of the second group
Since we have a common term of , we can combine like terms
So factors to
So this also means that factors to (since is equivalent to )
------------------------------------------------------------
So factors to
==============================================================
Answer:
So completely factors to 
|
|
|