SOLUTION: Nuts costing $9 per kg are to be mixed with nuts costing $6.5 per kg to make 10 kg of nuts costing $8 per kg. How many kg of nuts costing $9 per kg should be used?
Please help me!
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Question 189685: Nuts costing $9 per kg are to be mixed with nuts costing $6.5 per kg to make 10 kg of nuts costing $8 per kg. How many kg of nuts costing $9 per kg should be used?
Please help me!! Answer by jim_thompson5910(35256) (Show Source):
Since we "to make 10 kg of nuts", this gives the first equation .
Also, since "$9 per kg are to be mixed with nuts costing $6.5 per kg to make 10 kg of nuts costing $8 per kg.", this means that . Multiply 8 and 10 to get 80. So the equation then becomes . Finally, multiply EVERY term by 10 to make every number a whole number. So the equation then becomes
So we have the system of equations:
Let's solve by substitution
Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to solve for y.
So let's isolate y in the first equation
Start with the first equation
Subtract from both sides
Rearrange the equation
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Since , we can now replace each in the second equation with to solve for
Plug in into the second equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.