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Question 189666: I am having problems finding the vertex of this problem.. could someone please help.
Problem : Consider the Quadratic function f(x)=4x^2-64. Its vertex is ( ? , ?) Its x-intercepts are x= (?,?) Its y- intercept is y= ?
How do you find the vertex from an equation like this, I know the formula f(x) = (x-h)^2+k plays a part but I am not sure how it relates to the equation.
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website! Vertex:
In order to find the vertex, we first need to find the x-coordinate of the vertex.
To find the x-coordinate of the vertex, use this formula: .
Start with the given formula.
From , we can see that , , and .
Plug in and .
Multiply 2 and to get .
Divide.
So the x-coordinate of the vertex is . Note: this means that the axis of symmetry is also .
Now that we know the x-coordinate of the vertex, we can use it to find the y-coordinate of the vertex.
Start with the given equation.
Plug in .
Square to get .
Multiply and to get .
Combine like terms.
So the y-coordinate of the vertex is .
So the vertex is .
X-Intercept(s):
Remember, the x-intercepts occur when
Start with the given equation.
Plug in .
Notice we have a quadratic equation in the form of where , , and
Let's use the quadratic formula to solve for x
Start with the quadratic formula
Plug in , , and
Square to get .
Multiply to get
Rewrite as
Add to to get
Multiply and to get .
Take the square root of to get .
or Break up the expression.
or Combine like terms.
or Simplify.
So the answers are or
This means that the x-intercepts are (4,0) and (-4,0)
Y-Intercept:
Remember, the y-intercept occurs when
Start with the given equation.
Plug in .
Square to get .
Multiply and to get .
Combine like terms.
So the y-intercept is (0,-64)
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