(6x²-13x+4)÷(2x-1)
Start with this:
----------
2x-1)6x²-13x+4
Divide 2x into 6x², getting 3x.
Write the 3x over the -13x
3x
----------
2x-1)6x²-13x+4
Multiply the 3x by the 2x-1 getting
6x²-3x, and write that underneath the 6x²-13x,
and draw line underneath
3x
----------
2x-1)6x²-13x+4
6x²- 3x
-------
Now subtract (-13x)-(-3x) = -13x+3x = -10x
When we subtract the 6x² from the 6x², we
just get 0 so we do not write anything under
the 6x². So we write -10x underneath the
line.
3x
----------
2x-1)6x²-13x+4
6x²- 3x
-------
-10x
Now we bring down the +4
3x
----------
2x-1)6x²-13x+4
6x²- 3x
-------
-10x+4
Divide 2x into -10x, getting -5.
Write the -5 over the +4
3x-5
----------
2x-1)6x²-13x+4
6x²- 3x
-------
-10x+4
Multiply the -5 by the 2x-1 getting
-10x+5, and write that underneath the -10x+4,
and draw line underneath
3x-5
----------
2x-1)6x²-13x+4
6x²- 3x
-------
-10x+4
-10x+5
------
Now subtract (+4)-(+5) = 4-5 = -1.
When we subtract the -10x from the -10x, we
just get 0 so we do not write anything under
the -10x. So we write -1 underneath the
line.
3x-5
----------
2x-1)6x²-13x+4
6x²- 3x
-------
-10x+4
-10x+5
------
-1
Now we use the rule to write the answer:
or it is a little simpler written this way:
Edwin
