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| Question 189199:  Solve each of these system of equations.
 1) x + 2y + z = 10
 2x - y + 3z = -5
 2x - 3y - 5z = 27
 
 
 a) x = 4, y = 7, z = -5
 b) x = -5, y = 4, z =7
 c) x = 7, y = -5, z = 4
 d) x = 7, y = 4, z = -5
 
 On this question use the RREF function on your calculator
 2)  3x + y + z = 4
 2x + 2y + 3z = 3
 x + 3y + 2z = 5
 
 
 a) x = -1, y = 2, z = 1
 b) x = 2, y = 1, z = -1
 c) x = 1, y = 2, z = -1
 d) x = 1, y = -1, z = 2
 May you explain how to solve these questions?
 Answer by Alan3354(69443)
      (Show Source): 
You can put this solution on YOUR website! Solve each of these system of equations. 1) x + 2y + z = 10
 2x - y + 3z = -5
 2x - 3y - 5z = 27
 
 a) x = 4, y = 7, z = -5
 b) x = -5, y = 4, z =7
 c) x = 7, y = -5, z = 4
 d) x = 7, y = 4, z = -5
 --------------------
 x + 2y + z = 10
 2x - y + 3z = -5
 2x - 3y - 5z = 27
 There's more than one way to do these.  If you get one on a timed test, and you have 4 solutions to choose from, as in this one, sub the values in to find which of the 4 it is.  That's quicker by far, IF you don't have to show your work for the test.
 Then there's elimination and substitution.  You pick one of the 3 variables and eliminate it from 2 of the equations.  x is as good as any for this problem.
 Multiply by whatever is needed to get the same coeffs for all 3 eqns, in this case eqn 1 times 2 will do it.
 x + 2y + z = 10 -->
 2x + 4y + 2z = 20
 2x - y + 3z = -5
 2x - 3y - 5z = 27
 Then subtract one eqn, the 3rd, from the 1st and the 2nd.
 2x + 4y + 2z = 20
 2x - 3y - 5z = 27
 ----------------- Subtract
 0x + 7y + 7z = -7  eqn A
 --------------
 2x - y + 3z = -5
 2x - 3y - 5z = 27
 ----------------- Subtract
 0x + 2y + 8z = -32 eqn B
 Now there are 2 eqns in 2 variables, A and B.
 Multiply again to get the same coeffs
 y + z = -1
 y + 4z = -16
 ------------ Subtract
 0y -3z = 15
 z = -5 zzzzzzzzzzzzzzzzzzzzzzzzzzzz
 ------------
 y + z = -1
 y = 4 yyyyyyyyyyyyyyyyyyyyyyyyyyyyyy
 ------------
 x + 2y + z = 10
 x = 7 xxxxxxxxxxxxxxxxxxxxxxxxxxxx
 That's answer d.
 --------------------
 Another method is determinants.  I made an Excel sheet that does these up to 4 by 4.
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 I don't have a calculator that does these.
 
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