SOLUTION: ROOT:5-x = x-3
do I first set both sides squared to get rid of the root? this again says check all proposed solutions which I don't understand.
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do I first set both sides squared to get rid of the root? this again says check all proposed solutions which I don't understand.
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Question 189149: ROOT:5-x = x-3
do I first set both sides squared to get rid of the root? this again says check all proposed solutions which I don't understand. Answer by edjones(8007) (Show Source):
You can put this solution on YOUR website! sqrt(5-x)=x-3
5-x=x^2-6x+9 square each side.
x^2-5x+4=0 subtract the left side from the right.
(x-4)(x-1)=0 factor
x=4, x=1 These are the proposed solutions. Now you have to put them into the original equation and check to see if the solution is a true one or if it is extraneous.
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sqrt(5-4)=4-3
sqrt(1)=1 true
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sqrt(5-1)=1-3
2=-2 extraneous
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Ed
