SOLUTION: find the equation for a circle with ends of its diameter at points p(5,1) and Q(7,3). Write the answer in standard form. A. (x+3)^2+(y-2)^2=32 B. x^2+y^2=32 C. (x+6)^2+(y-2)^2

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: find the equation for a circle with ends of its diameter at points p(5,1) and Q(7,3). Write the answer in standard form. A. (x+3)^2+(y-2)^2=32 B. x^2+y^2=32 C. (x+6)^2+(y-2)^2      Log On


   

Question 189017: find the equation for a circle with ends of its diameter at points p(5,1) and Q(7,3). Write the answer in standard form.
A. (x+3)^2+(y-2)^2=32
B. x^2+y^2=32
C. (x+6)^2+(y-2)^2=2
D. (x-6)^2+(y-2)^2=2
please choose A,B,C or D
Answer by solver91311(24713) About Me  (Show Source):
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Use the mid-point formulas to calculate the coordinates of the mid-point of the diameter line segment which is the center of the circle.





where

and

are the coordinates of the given points.

Once you have the center determined, use the distance formula to calculate the distance from either given point to the center to determine the radius:



The equation of a circle with center at

and radius r is



John