SOLUTION: Katy leaves City A for City B at 7 A.M., driving at 47 mi/h. At 9 A.M., Jensen leaves City B for City A, driving at 55 mi/h along the same route. If the cities are 298 mi apart, at
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Question 188992: Katy leaves City A for City B at 7 A.M., driving at 47 mi/h. At 9 A.M., Jensen leaves City B for City A, driving at 55 mi/h along the same route. If the cities are 298 mi apart, at what time (A.M.) will they meet? [NOTE: Give the number of your answer only - do not label the answer.] Answer by jonvaliente(64) (Show Source):
You can put this solution on YOUR website! At 9AM (2 hours after Kay left City A), Katy would have already traveled:
47*2=94 miles
That leaves a distance of:
298-94=204 miles left to City B
If we let x = no of hours that Katy and Jensen needs to travel to cover all 204 miles, then:
This gives us:
Dividing both sides by 102:
The answer is 2
