SOLUTION: Can you please help me with this equation? Calculate the value of the discriminant of {{{x^2+2x+1=0}}}

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Question 188942: Can you please help me with this equation?
Calculate the value of the discriminant of x%5E2%2B2x%2B1=0
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
The onsite solver does this well.
Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc)
Quadratic equation ax%5E2%2Bbx%2Bc=0 (in our case 1x%5E2%2B2x%2B1+=+0) has the following solutons:

x%5B12%5D+=+%28b%2B-sqrt%28+b%5E2-4ac+%29%29%2F2%5Ca

For these solutions to exist, the discriminant b%5E2-4ac should not be a negative number.

First, we need to compute the discriminant b%5E2-4ac: b%5E2-4ac=%282%29%5E2-4%2A1%2A1=0.

Discriminant d=0 is zero! That means that there is only one solution: x+=+%28-%282%29%29%2F2%5C1.
Expression can be factored: 1x%5E2%2B2x%2B1+=+%28x--1%29%2A%28x--1%29

Again, the answer is: -1, -1. Here's your graph:
graph%28+500%2C+500%2C+-10%2C+10%2C+-20%2C+20%2C+1%2Ax%5E2%2B2%2Ax%2B1+%29