Write the pattern as A x B = C x C - 1
The pattern does appears to continue
(A x B) = (C x C) - 1
--------------------------
19 x 21 = 20 x 20 - 1 = 399
39 x 41 = 40 x 40 - 1 = 1599
59 x 61 = 60 x 60 - 1 = 3599
79 x 81 = 80 x 80 - 1 = 6399
99 x 101 = 100 x 100 - 1 = 9999
119 x 121 = 120 x 120 - 1 = 14399
but we must find out for certain if the pattern
continues forever:
The numbers in both C columns are multiples of 20,
so the general expression for them is C = 20n
The numbers in column A are 1 less than the numbers
in column C, so the general expression for them is
A = 20n-1
The numbers in column B are 1 more than the numbers
in column C, so the general expression for them is
B = 20n+1
Now we want to find out if it is always true that'
A x B = C x C - 1
So we substitute
(20n-1)(20n+1) = (20n)(20n)-1
Then we simplify each side:
400n2-1 = 400n2-1
so since both sides are the same, regardless
of n, we now know for certain that the pattern
will continue forever.
Edwin