SOLUTION: solve x^3-3x^2-28x=0

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Question 18867: solve x^3-3x^2-28x=0
Answer by xcentaur(357) About Me  (Show Source):
You can put this solution on YOUR website!
x^3-3x^2-28x=0
This is a cubic equation (x^3) and so will have 3 roots.


Taking x common,
x(x^2-3x-28)=0
So we get,
x=0,x^2-3x-28=0...[*]


Solving the quadratic
x^2-3x-28=0
(x-7)(x+4)=0
x=7,-4


therefore we get,
x=0,7,-4


Hope this helps,
Prabhat