SOLUTION: Jim walks 5mph on a steady day. On a windy day Jim walks 10 miles with the wind, and 7 miles against the wind in the same amount of time. What is the rate of the wind?

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Question 188499: Jim walks 5mph on a steady day. On a windy day Jim walks 10 miles with the wind, and 7 miles against the wind in the same amount of time. What is the rate of the wind?
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let w= the rate of the wind
Let j= Jim's rate of walking without wind
given:
j+=+5 mi/hr
10+=+%28j+%2B+w%29%2At
7+=+%28j+-+w%29%2At
--------------------
10+=+%285+%2B+w%29%2At
(1) 10+=+5t+%2B+wt
and
7+=+%285+-+w%29%2At
(2) 7+=+5t+-+wt
Add (1) and (2)
(3) 17+=+10t
(3) t+=+1.7
and from (1)
(1) 10+=+5%2A1.7+%2B+w%2A1.7
(1) 10+=+8.5+%2B+1.7w
(1) 1.7w+=+1.5
(1) w+=+.882 mi/hr
check:
(2) 7+=+5t+-+wt
(2) 7+=+5%2A1.7+-+.882%2A1.7
(2) 7+=+8.5+-+1.5
(2) 7+=+7
OK