Question 188485: Bob has 26 coins totalling $2.15. If he has only nickels and dimes, how many of each coin does he have? Answer by Mathtut(3670) (Show Source):
You can put this solution on YOUR website! let n and d be the number of nickels and dimes respectively
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n+d=26...............eq 1
.05n+.1d=2.15........eq 2
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rewrite eq 1 to n=26-d and plug that value into eq 2
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.05(26-d)+.1d=2.15
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1.3-.05d+.1d=2.15
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.05d=.85
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d=17 number of dimes
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n=26-d=26-17=9 number of nickels
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