SOLUTION: find the coordinates of the vertex & y-intercept of the parabola y=x^2+4x

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Question 188482: find the coordinates of the vertex & y-intercept of the parabola y=x^2+4x
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
y=x%5E2%2B4x%2B4%29-4
:
y=%28x%2B2%29%5E2-4
:
vertex is at (-2,-4)
:
y intercept is found when setting x t zero
:
y=0%5E2%2B4%280%29=0.......so y intercept is 0: (0,0)