SOLUTION: find the equation for the parabola with a vertex at (5,-3) and passes through (-5,-7) 1) y= ? 2) now, write the equation in the form of y=Ax^2+Bx+C

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Question 188480: find the equation for the parabola with a vertex at (5,-3) and passes through (-5,-7)
1) y= ?
2) now, write the equation in the form of y=Ax^2+Bx+C
Answer by Mathtut(3670) About Me  (Show Source):
You can put this solution on YOUR website!
y-k=a%28x-h%29%5E2 where (h,k) is vertex
:
we have a point (x,y) also (-5,-7).......so lets plug these in and find a
:
-7-%28-3%29=a%28-5-%285%29%29%5E2
:
-4=a%2810%29%5E2
:
a=-4%2F100=-1%2F25
:
y%2B3=%28-1%2F25%29%28x-5%29%5E2
:
y%2B3=%28-1%2F25%29%28x%5E2-10x%2B25%29
:
y%2B3=%28-1%2F25%29x%5E2%2B%282%2F5%29x-1
:
y=%28-1%2F25%29x%5E2%2B%282%2F5%29x-4