SOLUTION: Simplify. State any restrictions on the variable.. please help me with these to. thanks for your help and time.
1. x^2-25/x^2+3x
2. 4x^2-25/2x^2+3x-20
Algebra ->
Rational-functions
-> SOLUTION: Simplify. State any restrictions on the variable.. please help me with these to. thanks for your help and time.
1. x^2-25/x^2+3x
2. 4x^2-25/2x^2+3x-20
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You can put this solution on YOUR website! If zero was in the denominator the terms would be undefined.....
1 in the denominator lets factor the term...
:
x(x+3).....the restriction is that the denominator cannot be zero...so set
x(x+3)=0--->now set both of those factors equal to 0.x=0 and x+3=0,so the restriction is that x cannot be 0 or -3
:
2) factor the denominator (2x-5)(x+4)....now set each factor equal to zero.
:
2x-5=0 and x+4=0....so the restriction is that x cannot be 5/2 or -4.
:
If zero was in the denominator the term would be undefined.....