SOLUTION: The total of two numbers is 16. The first number plus 2 more than 3 times the second equals 18. (Let x be the first number)

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Question 188138This question is from textbook Beginning & Intermediate Algebra
: The total of two numbers is 16. The first number plus 2 more than 3 times the second equals 18. (Let x be the first number) This question is from textbook Beginning & Intermediate Algebra

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!


The two numbers --> x (1st) & y (2nd)

1st condtn: Sum is 16, x+y=16 EQN1
2nd condtn: The first number plus 2 --> x+2.
Then more than 3 times the second --> x+2+3y.
They are equal to 18 --> x+2+3y=18 EQN2

In EQN1 we get, y=16-x EQN3, and subst. in EQN2:
x%2B2%2B3%28highlight%2816-x%29%29=18
Expand & Combine similar terms:
x%2B48-3x=18-2 ----> 48-16=3x-x ---> 32=2x ---> cross%2832%2916%2Fcross%282%29=cross%282%29x%2Fcross%282%29
x=16 (1st no.) Go back EQN3:
y=16-16=0 (2nd no.)

Check in EQN2:
16%2B2%2B3%280%29=18
18=18
Thank you,
Jojo