SOLUTION: Find all of the zeros of f(x)=x^3-5x^2+8x-6
P=(+or-)1, (+or-)2, (+or-)3, (+or-)6
q= 1
I need help on the division part.
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-> SOLUTION: Find all of the zeros of f(x)=x^3-5x^2+8x-6
P=(+or-)1, (+or-)2, (+or-)3, (+or-)6
q= 1
I need help on the division part.
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Question 188137This question is from textbook algebra2
: Find all of the zeros of f(x)=x^3-5x^2+8x-6
P=(+or-)1, (+or-)2, (+or-)3, (+or-)6
q= 1
I need help on the division part. This question is from textbook algebra2
You can put this solution on YOUR website! I graphed it and found that x=3 is a root.
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Find all of the zeros of f(x)=x^3-5x^2+8x-6
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Using synthetic division:
3)....1....-5....8....-6
.......1.....-2...2...|..0
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Now use the quadratic formula on x^2 -2x + 2 to find the other roots.
x = [2 +- sqrt(4 - 4*1*2) /2
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x = [2 +- sqrt(-4)]/2
x = [1 +- i]
x = 1+i or x = 1-i or x = 3
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Cheers,
Stan H.
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