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Question 188109: Not sure if I selected the right catagory but I'm lost with this and need step by step help so I can answer other homework problems and be ready for test.
Question:
A garden is shaped like a rectangle whose perimeter is 86 feet. The length is 7 feet more than the width. Find the length and the width.
Can you show me step by step how to solve problems like this, please?
Thanks
Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website! Start with the formula for the perimeter (P) of a rectangle:
P = 2(L+W) where L = length and W = width.
The problem states that the length (L) is 7 feet more than the width (W) and you can express this as: L = W+7.
The problem also states that the perimeter (P) is 86 feet so you can write: P = 86.
Making these substitutions into the formula, you get:
86 = 2((W+7)+W) Simplify this.
86 = 2(2W+7) Divide both sides by 2.
43 = 2W+7 Subtract 7 from both sides.
36 = 2W Finally, divide both sides by 2.
18 = W or W = 18 feet.
The length, L = W+7, so L = 18+7 = 25 feet.
The length is 25 feet and the width is 18 feet.
Check:
P = 2(L+W) Substitute L = 25 and W = 18.
P = 2(25+18)
P = 2(43)
P = 86 feet.
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