SOLUTION: CAN ANYONE HELP WITH THIS PROBLEM ... I AM SO STUCK!! THANKS Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per mi

Click here to see ALL problems on Rate-of-work-word-problems

Question 188003: CAN ANYONE HELP WITH THIS PROBLEM ... I AM SO STUCK!! THANKS
Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start.
Let W represent the amount of water in the pond (in liters), and let T represent the number of minutes that water has been added. Write an equation relating W to T, and then graph your equation using the axes below.

Found 2 solutions by solver91311, ankor@dixie-net.com:
Answer by solver91311(24713) (Show Source):
You can put this solution on YOUR website!

How much water is in the pond just before they started to fill it? 700 liters.

How much water are they adding every minute? 35 liters.

So, after the first minute of filling: 700 + 35(1)

After the second minute of filling: 700 + 35(2)

After T minutes of filling: 700 + 35T

So:

John

Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website!
Owners of a recreation area are filling a small pond with water. They are adding water at a rate of 35 liters per minute. There are 700 liters in the pond to start.
Let W represent the amount of water in the pond (in liters), and let T represent the number of minutes that water has been added. Write an equation relating W to T, and then graph your equation using the axes below.
:
the equation would be: Total water (W) = 35L*minutes(T) + 700L
W = 35T + 700
:
Put T on the horizontal (x) and W on the vertical (Y)
Graph should look like this:

Note when T = 0, you have 700L, when T = 60, you have 35(60)+ 700 = 2800L