SOLUTION: b. The loan officer rates applicants for credit. Ratings are normally distributed. The mean is 240 and the standard deviation is 60. If 49 applicants are randomly chosen, what is t

Algebra ->  Probability-and-statistics -> SOLUTION: b. The loan officer rates applicants for credit. Ratings are normally distributed. The mean is 240 and the standard deviation is 60. If 49 applicants are randomly chosen, what is t      Log On


   



Question 187919: b. The loan officer rates applicants for credit. Ratings are normally distributed. The mean is 240 and the standard deviation is 60. If 49 applicants are randomly chosen, what is the probability that they will have a rating between 230 and 260? Round z scores to two decimal places
Answer by stanbon(75887) About Me  (Show Source):
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The loan officer rates applicants for credit. Ratings are normally distributed. The mean is 240 and the standard deviation is 60. If 49 applicants are randomly chosen, what is the probability that they will have a rating between 230 and 260? Round z scores to two decimal places
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z(230) = (230-240)/[60/sqrt(49)] = -1.1667
z(260) = (260-240)/[60/sqrt(49)] = 2.3333
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P(230 < z < 240) = P(-1.1667 < z < 2.333) = 0.8685
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Cheers,
Stan H.