SOLUTION: log base 3 (x) = log base 3 (1/x)+4
i understand that log base 3 (1/x) is subtracted so the problem could look something like this log base 3 (x) -log base 3 (1/x)=4
have one
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-> SOLUTION: log base 3 (x) = log base 3 (1/x)+4
i understand that log base 3 (1/x) is subtracted so the problem could look something like this log base 3 (x) -log base 3 (1/x)=4
have one
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Question 187879: log base 3 (x) = log base 3 (1/x)+4
i understand that log base 3 (1/x) is subtracted so the problem could look something like this log base 3 (x) -log base 3 (1/x)=4
have one question doesnt 1 and x become log base 3 (1)- log base 3 (x)
the answer is 9, -9 but i dont know how to set up the problem i am stuck Answer by solver91311(24713) (Show Source):
9 certainly could be (and is) the value of x that makes this equation a true statement, but -9 cannot be. The domain of the log function is:
So if you were to say:
What you would really be saying is: "Some undefined thing is equal to some other undefined thing plus 4." A patently absurd thing to say by any measure.
Having said all of that, here's how to do the problem correctly:
Now, use "The log of the quotient is the difference of the logs"
Remove the parentheses and use to write:
Since:
Where whomever gave you the answer of -9 may have gone wrong is they might have said:
And the roots of are 9 and -9, but you still have to go back to the original equation and consider any domain restrictions. Therefore, you must exclude the negative root.
