SOLUTION: The center of the circle (x+1)^2 + y^2 = 4
Please put the solution.. thank you for being so nice and helpful tutors..^^
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Please put the solution.. thank you for being so nice and helpful tutors..^^
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Question 187732: The center of the circle (x+1)^2 + y^2 = 4
Please put the solution.. thank you for being so nice and helpful tutors..^^ Answer by mgmoeab(37) (Show Source):
You can put this solution on YOUR website! The center of the circle (x+1)^2 + y^2 = 4
Remember the equation of a circle with center (h, k) is given by:
(x-x1)^2 + (y - y1)^2 = r^2 were the center is (x1, y1)
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in this case:
(x+1)^2 + y^2 = 4
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which can be written as:
(x-(-1))^2 + (y - 0)^2 = 2^2 were the center would be (-1, 0) and a radius of 2.
hope it helps!
