SOLUTION: who can help me to solve and find the right solution of this given! 1. y=-x+8 x-y=-1 2. 6x+y=-4 6x-y=-1 3. y=-x+8 x-y=-1 im getting too craz

Algebra ->  Graphs -> SOLUTION: who can help me to solve and find the right solution of this given! 1. y=-x+8 x-y=-1 2. 6x+y=-4 6x-y=-1 3. y=-x+8 x-y=-1 im getting too craz      Log On


   

Question 187688This question is from textbook algebra 1
: who can help me to solve and find the right solution of this given!


1. y=-x+8
x-y=-1


2. 6x+y=-4
6x-y=-1

3. y=-x+8
x-y=-1



im getting too crazy to find the right solution and the right answer please help naman!


THANK'S FOR HELPING ME AND I REALY APPRICIATE IT This question is from textbook algebra 1

Answer by jojo14344(1513) About Me  (Show Source):
You can put this solution on YOUR website!

We'll do the 1st one , and you do rest based on this oks. Besides it will bring confidence on you when you tackle problems like this.

GIVENsystem%28y=-x%2B8%28EQN1%29%2Cx-y=-1%28EQN2%29%29
Since you have value of "y" in EQN 1, substitute it on EQN2:
x-highlight%28-x%2B8%29=-1--->x%2Bx-8=-1--->2x=-1%2B8=7
cross%282%29x%2Fcross%282%29=7%2F2---->red%28x=7%2F2%29,

Substitute this X-Intercept in EQN 1:
y=-highlight%28%287%2F2%29%29%2B8=-7%2F2%2B8=%28-7%2B16%29%2F2=red%289%2F2%29,
There you go, Point of Intersection, (x,y)=(7/2,9/2)

Let's find the intercepts x and y:
In EQN 1, let fy=0------->0=-x%2B8---->highlight%28x=8%29, X-Intercept
let fx=0-------> y=0%2B8----->highlight%28y=8%29, Y-Intercept

In EQN 2, let fy=0 ------>x-0=-1----> highlight%28x-1%29
let fx=0 ------> 0-y=-1---->cross%28-1%29y%2Fcross%28-1%29=cross%28-1%291%2Fcross%28-1%29 ----->highlight%28y=1%29, Y-Intercept

Let's plot the points:
----> RED (EQN1); GREEN (EQN 2)

Now, you can do the rest.
Thank you,
Jojo