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Question 187559This question is from textbook algebra 1
: please help me to solve this problem in geometry
state condition for parallelness or prpendicularity of two lines determine weather the graph of the equation are parallel,perpendicular or neither?
1. y+3=6x
-6x-y=2
2. y=-4x+3
5y+10x=20
3. y=2x+7
5y+10x=20
4.-3x+y=4
3x-y=-6
5. 6y-x=-12
1/6x+y=3
6. x+y=6
4y-4x=12
7. y=-x+8
x-y=-1
8. 6x+y=-4
6x-y=-1
9. y=-x+8
x-y=-1
i need answer before our class report on monday
thanks for your time i realy appreciate it..
This question is from textbook algebra 1
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! please help me to solve this problem in geometry
state condition for parallelness or prpendicularity of two lines determine weather the graph of the equation are parallel,perpendicular or neither?
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Lines are parallel if they have the same slope.
They are perpendicular when the slopes are the negative inverses, eg,
3 and -1/3, or 1 and -1.
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1. y+3=6x --> y = 6x-3
-6x-y=2
Sub for y into the 2nd eqn
-6x -(6x-3) = 2
-12x + 3 = 2
-12x = -1
x = 1/12
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y = 6x-3
y = -5/2
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2. y=-4x+3
5y+10x=20
Do this one in the same way as #1.
3. y=2x+7
5y+10x=20
This one too.
4.
-3x+y=4
3x-y=-6
--------- Add these 2 eqns
0x+0y = -2
This has no solution. If you graph it, you'll see the lines are parallel.
You can get (free) software at www.padowan.dk.com/graph/ to do these.
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5. 6y-x=-12
1/6x+y=3 --> x+6y = 18
Do as in #1
6. x+y=6
4y-4x=12
7. y=-x+8
x-y=-1
8. 6x+y=-4
6x-y=-1
9. y=-x+8
x-y=-1
email me via the thank you note if you have questions, or want me to check your work.
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