SOLUTION: {{{8/(x^2-4)+ (2x)/(x^2+4x+4) - 6/(x+2)}}} I got {{{(-4x^2+4x+8)/((x+2)^2(x-2))}}}

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: {{{8/(x^2-4)+ (2x)/(x^2+4x+4) - 6/(x+2)}}} I got {{{(-4x^2+4x+8)/((x+2)^2(x-2))}}}      Log On


   



Question 187261: 8%2F%28x%5E2-4%29%2B+%282x%29%2F%28x%5E2%2B4x%2B4%29+-+6%2F%28x%2B2%29
I got %28-4x%5E2%2B4x%2B8%29%2F%28%28x%2B2%29%5E2%28x-2%29%29

Answer by Edwin McCravy(20064) About Me  (Show Source):
You can put this solution on YOUR website!

Your 8 in the top should have been 40.

8%2F%28x%5E2-4%29%2B+%282x%29%2F%28x%5E2%2B4x%2B4%29+-+6%2F%28x%2B2%29 

Factor the first two denominators:

8%2F%28%28x-2%29%28x%2B2%29%29%2B+%282x%29%2F%28%28x%2B2%29%28x%2B2%29%29+-+6%2F%28x%2B2%29

Now let's create the LCD:

%28x-2%29 appears 1 time in the first denominator,
0 time in the second denominator and 0 times in the
third denominator.  That's at most 1 time, so it
has to be included in the LCD 1 time

%28x%2B2%29 appears 1 time in the first denominator,
2 times in the second denominator and 1 times in the
third denominator.  That's at most 2 times, so it
has to be included in the LCD 2 times

So the LCD contains %28x-2%29 1 time and %28x%2B2%29
2 times. So:

LCD = %28x-2%29%28x%2B2%29%28x%2B2%29

Each of the three terms must be rewritten so that each
fraction has the LCD as its denominator.

The first fraction is

8%2F%28%28x-2%29%28x%2B2%29%29

Its denominator needs another %28x%2B2%29 factor to become
the LCD, so we multiply its numerator and denominator by
%28x%2B2%29

The second fraction is

%282x%29%2F%28%28x%2B2%29%28x%2B2%29%29 

Its denominator needs an %28x-2%29 factor to become
the LCD, so we multiply its numerator and denominator by 
%28x-2%29

The third fraction is

-6%2F%28x%2B2%29

Its denominator needs another %28x%2B2%29 factor and
another %28x-2%29 factor to become the LCD, so we 
multiply its numerator and denominator by 
%28x%2B2%29%28x-2%29

So

8%2F%28%28x-2%29%28x%2B2%29%29%2B+%282x%29%2F%28%28x%2B2%29%28x%2B2%29%29+-+6%2F%28x%2B2%29

now becomes:



Multiply out the numerators only:

  

The last numerator still needs one more step to be multiplied
out:

  

Now we combine all the numerators over the LCD:




Remove all the parentheses on the top, but not on the bottom.

%288x%2B16%2B+2x%5E2-4x-6x%5E2%2B24%29%2F%28%28x-2%29%28x%2B2%29%28x%2B2%29%29

Combine all like terms on the top:
 
%284x%2B40-4x%5E2%29%2F%28%28x-2%29%28x%2B2%29%28x%2B2%29%29

If you like you may arrange the top in descending powers of x:

%28-4x%5E2%2B4x%2B40%29%2F%28%28x-2%29%28x%2B2%29%28x%2B2%29%29

and you see that there is a 40 where you had 8.  If
you like you can factor -4 out of the top, and as you
did,  write %28x%2B2%29%5E2 instead of %28x%2B2%29%28x%2B2%29 in
the bottom:

%28-4%28x%5E2-x-10%29%29%2F%28%28x-2%29%28x%2B2%29%5E2%29

But we find that the quadratic in the parenthese does not
factor, so that's as far as we can go.

Edwin