SOLUTION: 10^log^(2x+7) = 8

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Question 187182: 10^log^(2x+7) = 8
Answer by 543210aaa(2) About Me  (Show Source):
You can put this solution on YOUR website!
You may use the following rule:
m%5E%28log%28m%2Ca%29%29=a
Using this LHS of the question becomes 2x+7.
=>2x+7=8
=>2x=1
=>x=1/2
Satisfied???