SOLUTION: log(2x^2+3x) = log(10x+30)

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Question 187166: log(2x^2+3x) = log(10x+30)
Found 2 solutions by user_dude2008, uday1435:
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
log(2x^2+3x) = log(10x+30)

2x^2+3x = 10x+30

2x^2+3x - 10x - 30 = 0

2x^2-7x-30 = 0

(x-6)(2x+5) = 0

x-6=0 or 2x+5=0

Ans: x=6 or x=-5/2

Answer by uday1435(57) About Me  (Show Source):
You can put this solution on YOUR website!
log(2x^2+3x) = log(10x+30)
2x^3 + 3x = 10x +30
2x^3 – 7x – 30 = 0
(2x+5)(x – 6) = 0
So x = 6 or – (5/2)



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