SOLUTION: log(x^2+19) = 2
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Question 187165
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log(x^2+19) = 2
Answer by
user_dude2008(1862)
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log is assumed to be base 10
log(x^2+19) = 2
x^2+19 = 10^2
x^2+19 = 100
x^2 = 100 - 19
x^2 = 81
x=-9 or x=9