SOLUTION: please factor out this polynomial. 4x+12xy+9y^2 thank you

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Question 187134: please factor out this polynomial.

4x+12xy+9y^2

thank you

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
I'm assuming that the expression is really 4x%5E2%2B12xy%2B9y%5E2. If not, then let me know.




Looking at 4x%5E2%2B12xy%2B9y%5E2 we can see that the first term is 4x%5E2 and the last term is 9y%5E2 where the coefficients are 4 and 9 respectively.

Now multiply the first coefficient 4 and the last coefficient 9 to get 36. Now what two numbers multiply to 36 and add to the middle coefficient 12? Let's list all of the factors of 36:



Factors of 36:
1,2,3,4,6,9,12,18

-1,-2,-3,-4,-6,-9,-12,-18 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 36
1*36
2*18
3*12
4*9
6*6
(-1)*(-36)
(-2)*(-18)
(-3)*(-12)
(-4)*(-9)
(-6)*(-6)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 12? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 12

First NumberSecond NumberSum
1361+36=37
2182+18=20
3123+12=15
494+9=13
666+6=12
-1-36-1+(-36)=-37
-2-18-2+(-18)=-20
-3-12-3+(-12)=-15
-4-9-4+(-9)=-13
-6-6-6+(-6)=-12



From this list we can see that 6 and 6 add up to 12 and multiply to 36


Now looking at the expression 4x%5E2%2B12xy%2B9y%5E2, replace 12xy with 6xy%2B6xy (notice 6xy%2B6xy adds up to 12xy. So it is equivalent to 12xy)

4x%5E2%2Bhighlight%286xy%2B6xy%29%2B9y%5E2


Now let's factor 4x%5E2%2B6xy%2B6xy%2B9y%5E2 by grouping:


%284x%5E2%2B6xy%29%2B%286xy%2B9y%5E2%29 Group like terms


2x%282x%2B3y%29%2B3y%282x%2B3y%29 Factor out the GCF of 2x out of the first group. Factor out the GCF of 3y out of the second group


%282x%2B3y%29%282x%2B3y%29 Since we have a common term of 2x%2B3y, we can combine like terms

So 4x%5E2%2B6xy%2B6xy%2B9y%5E2 factors to %282x%2B3y%29%282x%2B3y%29


So this also means that 4x%5E2%2B12xy%2B9y%5E2 factors to %282x%2B3y%29%282x%2B3y%29 (since 4x%5E2%2B12xy%2B9y%5E2 is equivalent to 4x%5E2%2B6xy%2B6xy%2B9y%5E2)


note: %282x%2B3y%29%282x%2B3y%29 is equivalent to %282x%2B3y%29%5E2 since the term 2x%2B3y occurs twice. So 4x%5E2%2B12xy%2B9y%5E2 also factors to %282x%2B3y%29%5E2



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Answer:
So 4x%5E2%2B12xy%2B9y%5E2 factors to %282x%2B3y%29%5E2