SOLUTION: Rod agreed to mow a vacant lot for $12. It took him an an hour longer than he had anticipated, so he earned $1 per hour less than he had originally claculated. How long had he an
Algebra ->
Rate-of-work-word-problems
-> SOLUTION: Rod agreed to mow a vacant lot for $12. It took him an an hour longer than he had anticipated, so he earned $1 per hour less than he had originally claculated. How long had he an
Log On
Question 187123This question is from textbook
: Rod agreed to mow a vacant lot for $12. It took him an an hour longer than he had anticipated, so he earned $1 per hour less than he had originally claculated. How long had he anticipated that it would take him to mow the lot? This question is from textbook
You can put this solution on YOUR website! Rod agreed to mow a vacant lot for $12. It took him an an hour longer than he had anticipated, so he earned $1 per hour less than he had originally claculated. How long had he anticipated that it would take him to mow the lot?
----------------------------------------------------
Let original estimated time be "x" hours.
Then original pay per hour = (12/x) dollars per hour
------------------------------
New time to do the job: "x+1" hour.
Now original pay per hour = 12/(x+1) dollars per hour
----------------------------
Equation:
orinal pay per hour - new pay per hour = 1 dollar
12/x - (12/(x+1) = 1
12 = x(x+1)
x^2 + x - 12 = 0
(x+4)(x-3) = 0
Positive solution:
x = 3 hrs. (original estimated time to do the job)
==================================================
Cheers,
Stan H.
(