Question 187102This question is from textbook Algebra 2
: Hello I was doing my homework on quadratic functions and I have a question on a problem that my teacher never went over before.
1. Find a quadratic function that includes each set of values.
(1,-2),(2,-2),(3,-4)
Please show me work because I would like to know how to do it. Thank You
This question is from textbook Algebra 2
Answer by nerdybill(7384)   (Show Source):
You can put this solution on YOUR website! A quadratic looks like:
y = ax^2 + bx + c
.
The problem gives you three points:
(1,-2),(2,-2),(3,-4)
Which relates to:
(1,-2)
-2 = a(1)^2 + b(1) + c
-2 = a + b + c
.
(2,-2)
-2 = a(2)^2 + b(2) + c
-2 = 4a + 2b + c
.
(3,-4)
-4 = a(3)^2 + b(3) + c
-4 = 9a + 3b + c
.
Now, you have basically a "system of equations":
-2 = a + b + c
-2 = 4a + 2b + c
-4 = 9a + 3b + c
.
Can you finish the problem from here?
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