SOLUTION: Can you tell me how long it would take a locomotive traveling 3.53 miles per hour to travel 15 feet? 20 feet? 30 feet? Or, perhaps at least the formula for determining this sor

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Question 187052: Can you tell me how long it would take a locomotive traveling 3.53 miles per hour to travel 15 feet? 20 feet? 30 feet? Or, perhaps at least the formula for determining this sort of thing?
Many thanks!!!
Found 2 solutions by vleith, stanbon:
Answer by vleith(2983) About Me  (Show Source):
You can put this solution on YOUR website!
distance+=+rate+%2A+Time
In your case, the speed is given in mph and the distance are given in feet. So you need to fix that up
3.53mph = 3.53*5280 = 18638.4 feet/hour
So for 15 feet
15+=+18638.4+%2A+t
0.000805+=+t+ but that is in hours. So convert to seconds
0.000805+%2A+60+%2A+60+=+tInSeconds = 2.897 seconds

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Can you tell me how long it would take a locomotive traveling 3.53 miles per hour to travel 15 feet? 20 feet? 30 feet? Or, perhaps at least the formula for determining this sort of thing?
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3.53 miles/hr = 3.53[3280 feet/hr] or 18638.4 feet/hr = 310.64 feet/min
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Time to travel 15 ft:
= (310.64/310.64)*(feet/(60 sec/310.64)
= 1 foot/0.1931 second
= 15 feet/2.8972 seconds
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Time to travel 20 feet
= 20 feet/[20*0.1931 sec] = 20 feet / 3.8620 seconds
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Time to travel "x" feet
= x feet/[0.1931x sec]
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Cheers,
Stan H.