SOLUTION: Solve 2x^-7x-2=0

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Question 187034: Solve 2x^-7x-2=0
Answer by checkley75(3666) About Me  (Show Source):
You can put this solution on YOUR website!
2x^-7x-2=0
IF you mean: 2x^2-7x-2=0 then:
x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+
x=(7+-sqrt[-7^2-4*2*-2])/2*2
x=(7+-sqrt[49+16])/4
x=(7+-sqrt65)/4
x=(7+-8.062)/4
x=(7+8.062)/4
x=15.062/4
x=3.77 ans.
x=(7-8.062)/4
x=-1.062/4
x=-.266 ans.