Question 18696: hi.. i need help with writing and solving an equation in standard form. for instance.. y- intercept=8 and the slope is 3. does that mean the equation in standard form is 3x+y=-8?? I also need help with.. if the slope = 3/4 and y-intercept= -2 what's the equation in standard form and how can you get 3/4 to not be a fraction or negative? same with slope= 3/5 and passes through 0, -6.. i think that means the y-int. is -6 but how do you graph slopes that are fractions and write them in an equation. sorry it's such a long question but please help me.. thanks!!
Answer by Earlsdon(6294)   (Show Source):
You can put this solution on YOUR website! When you are given the slope (m) and the y-intercept (b), you can start by writing the equation in the slope-intercept form:  then convert it to standard form:  .
N.B. I've capitalized the A, B, and C in the standard form because the B here is not the b that represents the y-intercept.
You are given the y-intercept, b = 8 and the slope, m = 3, so you can write:
 as the slope-intercept form. Now convert to the standard form.
For the second problem, you are given the slope,  and the y-intercept,  . First, write the slope-intercept form of the equation:
 Simplify.
 Now convert to standard form:
 To clear the fractional x-coefficient, simply multiply through by the denominator, 4.
 Standard form sans (without) fractional x-coefficient.
On the third problem, you are correct that the the point (0, -6) is the y-intercept, so you can go through the same process as for the first two problems.
Start with the slope-intercept form.
 Now convert to standard form:
 and the clear the fraction, multiply through by the denominator, 5.
 Standard form sans fractional x-coefficient.
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