SOLUTION: the sum of the digits of a two-digit number is 9. if 45 is subtracted from the number, the digits of the number are reversed. find the number.

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Question 186851: the sum of the digits of a two-digit number is 9. if 45 is subtracted from the number, the digits of the number are reversed. find the number.
Answer by user_dude2008(1862) About Me  (Show Source):
You can put this solution on YOUR website!
"the sum of the digits of a two-digit number is 9" ----> t+u=9 ----> t=9-u

" 45 is subtracted from the number, the digits of the number are reversed" 10t+u-45=10u+t


10t+u-45=10u+t

10(9-u)+u-45=10u+9-u

90-10u+u-45=10u+9-u

45-9u=9u+9

45-9=9u+9u

36=18u

u=2

t=9-u

t=9-2

t=7

Original Number: 72