SOLUTION: Bob was thinking of a number between 5 and 15 that when squared and added to 23 equals the next number's square. What is the number? x(x)+23 = (x+1)2 This should read as "x s

Algebra ->  Customizable Word Problem Solvers  -> Numbers -> SOLUTION: Bob was thinking of a number between 5 and 15 that when squared and added to 23 equals the next number's square. What is the number? x(x)+23 = (x+1)2 This should read as "x s      Log On

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Question 186742: Bob was thinking of a number between 5 and 15 that when squared and added to 23 equals the next number's square. What is the number?
x(x)+23 = (x+1)2
This should read as "x squared plus 23 equals the quantity x+1 squared.
I couldn't type exponents, so my equation may not make sense as it was written!
Thank you!

Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
Bob was thinking of a number between 5 and 15 that when squared and added
to 23 equals the next number's square. What is the number?
:
You can write it:
x^2 + 23 = (x+1)^2
FOIL
x^2 + 23 = x^2 + 2x + 1
:
23 - 1 = x^2 - x^2 + 2x
:
22 = 2x
:
x = 11
;
:
Check
11^2 + 23 = 144
12^2 = 144