SOLUTION: I have 28 coins in my pocket, they are all either nickels and dimes. There are eight more nickels than dimes. The value of these coins is 1.90. How many nickels? How many answers s

Algebra ->  Linear-equations -> SOLUTION: I have 28 coins in my pocket, they are all either nickels and dimes. There are eight more nickels than dimes. The value of these coins is 1.90. How many nickels? How many answers s      Log On


   



Question 186637: I have 28 coins in my pocket, they are all either nickels and dimes. There are eight more nickels than dimes. The value of these coins is 1.90. How many nickels? How many answers should I have?Define my variable, define in terms? Translate this information into an equation? Thank You guys you all are life savers in my class.
Answer by nerdybill(7384) About Me  (Show Source):
You can put this solution on YOUR website!
I have 28 coins in my pocket, they are all either nickels and dimes. There are eight more nickels than dimes. The value of these coins is 1.90. How many nickels? How many answers should I have?Define my variable, define in terms? Translate this information into an equation? Thank You guys you all are life savers in my class.
.
Let d = number of dimes
and n = number of nickels
.
Since we have two unknowns, we'll need two equations.
.
from "I have 28 coins in my pocket"
n+d = 28 (equation 1)
from "There are eight more nickels than dimes." we get:
n = d+8 (equation 2)
.
Solve equation 1 for 'd':
n+d = 28
d = 28-n
.
Substitute the above into equation 2 and solve for n:
n = d+8
n = 28-n+8
2n = 28+8
2n = 36
n = 18 (number of nickels)
.