Question 186621: Write the slope-intercept form of an equation for a line that passes through (-1,0) and is perpendicular to the graph of 3x-5y=20.
Answer by vleith(2983)   (Show Source):
You can put this solution on YOUR website! First, find the slope of the given line
y = mx + b, so the slope of the given line is 3/5
The line perpendicular to this line has slope (-5/3) negative reciprocal
Now find the line that have slope -5/3 and passes thru (-1,0)
| Solved by pluggable solver: FIND a line by slope and one point |
What we know about the line whose equation we are trying to find out:
- it goes through point (-1, 0)
- it has a slope of -1.66666666666667
First, let's draw a diagram of the coordinate system with point (-1, 0) plotted with a little blue dot:
Write this down: the formula for the equation, given point  and intercept a, is
 (see a paragraph below explaining why this formula is correct)
Given that a=-1.66666666666667, and  , we have the equation of the line:
Explanation: Why did we use formula  ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point ( ,  ) lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (, ):  Here, we know a, , and , and do not know b. It is easy to find out:  . So, then, the equation of the line is:  .
Here's the graph:
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