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| Question 186610:  i need help with the following word problem:
 a museum charges $10 for a regular admission ticket, but members recieve a discount of $3 and students are admitted for $5. Last saturday, 750 tickets were sold for a total of $5400. if more 20 student tickets than regular tickets were sold, how many of each type of ticket were sold?
 thanks!
 Answer by ankor@dixie-net.com(22740)
      (Show Source): 
You can put this solution on YOUR website! museum charges $10 for a regular admission ticket, but members receive a discount of $3 and students are admitted for $5. Last Saturday, 750 tickets were sold for
 a total of $5400. if more 20 student tickets than regular tickets were sold,
 how many of each type of ticket were sold?
 :
 Let x = no. of reg tickets ($10)
 Let y = no. of member ticket ($7)
 Let z = no. of students ($5)
 :
 No. of tickets equation:
 x + y + z = 750
 :
 Total$ equation
 10x + 7y + 5z = 5400
 :
 "20 student tickets than regular tickets were sold,"
 z = (x+20)
 :
 We know y = 750 - x - z; substitute (x+20) for z
 y = 750 - x - (x+20)
 y = 750 - 2x - 20
 y = (730 - 2x)
 :
 Substitute for y and z in the Total$ equation, find x:
 10x + 7(730-2x) + 5(x+20) = 5400
 Get rid of the brackets
 10x + 5110 - 14x + 5x + 100 = 5400
 10x - 14x + 5x + 5210 = 5400
 x = 5400 - 5210
 x = 190 reg tickets
 :
 y = 730 - 2x
 y = 730 - 380
 y = 350 member tickets
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 z = x + 20
 z = 190 + 20
 z = 210 students tickets
 ;
 :
 Check solutions in both equations
 190 + 350 + 210 = 750
 and
 10(190) + 7(350) + 5(210) =
 1900 + 2450 + 1050 = $5400
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